As for me, curly braces serve good substitution for concatenation, and they are quicker to type and code looks cleaner. Remember to use double quotes (" ") as their content is parced by php, because in single quotes (' ') you'll get litaral name of variable provided:
<?php
$a = '12345';
// This works:
echo "qwe{$a}rty"; // qwe12345rty, using braces
echo "qwe" . $a . "rty"; // qwe12345rty, concatenation used
// Does not work:
echo 'qwe{$a}rty'; // qwe{$a}rty, single quotes are not parsed
echo "qwe$arty"; // qwe, because $a became $arty, which is undefined
?>
PHP.mk документација
Низа
Почист и полокален преглед на PHP референцата, со задржана структура од PHP.net и подобра читливост за примери, секции и белешки.
Патека
language.operators.string.php
Локална патека за оваа страница.
Извор
php.net/manual/en
Оригиналниот HTML се реупотребува и локално се стилизира.
Режим
Прокси + превод во позадина
Кодовите, табелите и белешките остануваат читливи во истиот тек.
Референца
language.operators.string.php
Низа
Референца за `language.operators.string.php` со подобрена типографија и навигација.
Оператори на низи
Постојат два string operators. The first is the concatenation operator ('.'), which returns the concatenation of its right and left arguments. The second is the concatenating assignment operator ('.='), which appends the argument on the right side to the argument on the left side. Please read Оператори за доделување Користење на PHP од командната линија
Пример #1 Конкатенација на низи
<?php
$a = "Hello ";
$b = $a . "World!"; // now $b contains "Hello World!"
var_dump($b);
$a = "Hello ";
$a .= "World!"; // now $a contains "Hello World!"
var_dump($a);
?>Белешки од корисници 6 белешки
K.Alex ¶
пред 13 години
anders dot benke at telia dot com ¶
21 години пред
A word of caution - the dot operator has the same precedence as + and -, which can yield unexpected results.
Example:
<php
$var = 3;
echo "Result: " . $var + 3;
?>
The above will print out "3" instead of "Result: 6", since first the string "Result3" is created and this is then added to 3 yielding 3, non-empty non-numeric strings being converted to 0.
To print "Result: 6", use parantheses to alter precedence:
<php
$var = 3;
echo "Result: " . ($var + 3);
?>
Стивен Клеј ¶
20 години пред
<?php
"{$str1}{$str2}{$str3}"; // one concat = fast
$str1. $str2. $str3; // two concats = slow
?>
Use double quotes to concat more than two strings instead of multiple '.' operators. PHP is forced to re-concatenate with every '.' operator.
hexidecimalgadget at hotmail dot com ¶
пред 17 години
If you attempt to add numbers with a concatenation operator, your result will be the result of those numbers as strings.
<?php
echo "thr"."ee"; //prints the string "three"
echo "twe" . "lve"; //prints the string "twelve"
echo 1 . 2; //prints the string "12"
echo 1.2; //prints the number 1.2
echo 1+2; //prints the number 3
?>
biziclop ¶
3 години пред
Some bitwise operators (the and, or, xor and not operators: & | ^ ~ ) also work with strings too since PHP4, so you don't have to loop through strings and do chr(ord($s[i])) like things.
See the documentation of the bitwise operators: https://www.php.net/operators.bitwise
<?php var_dump(
('23456787654' ^ 'zVXYYhoXDYP'), // 'Hello_World'
('(!($)^!)@$@' | '@ddhfIvn2H$'), // 'hello_world'
('{}~|o!Wo{|}' & 'Lgmno|Wovmf'), // 'Hello World'
(~'<0-14)(98' & '}}}}}}}}}') // 'AMPLITUDE'
); ?>
Live demo: https://3v4l.org/MnFeb
mariusads::at::helpedia.com ¶
пред 17 години
Be careful so that you don't type "." instead of ";" at the end of a line.
It took me more than 30 minutes to debug a long script because of something like this:
<?
echo 'a'.
$c = 'x';
echo 'b';
echo 'c';
?>
The output is "axbc", because of the dot on the first line.