if you want to remove header information about php version (x-powered-by), you can use:

header_remove('x-powered-by');

alternatively, if you don't have php 5.3 installed, you can do the same thing using "header" command:

header('x-powered-by:');

don't forget the ':' character at the end of the string!

expose_php is php.ini only!

this won't work:
ini_set('expose_php',0);

works:
header_remove('x-powered-by');

If you are using this:

#!/usr/local/bin/php

You can add "-q" at the end of it and the headers will be removed, beacuse header_remove will not remove "Content-type"

#!/usr/local/bin/php -q

When called from a command-line process, this function does nothing when passed a specific header to remove, but it does nonetheless work properly when called with no arguments to remove all headers.

Thus, when unit-testing or executing in some other test harness, if the code you are testing may call `header_remove()`, with the UOPZ and XDebug extensions loaded, you could use the following in order to more effectively test that the expected headers are set [which you would do by inspecting the array returned by `xdebug_get_headers()` after running the code under test, as `headers_list()` does not work despite the headers actually being stored internally as normal]:

<?php
uopz_set_return(
  'header_remove',
  function($name = null) {
    if ($name !== null) {
      $pattern = '/^' . preg_quote($name, '/') . ':/i';
      $headers = array_filter(
        xdebug_get_headers(),
        function($header) use($pattern) {
          return !preg_match($pattern, $header);
        }
      );
    }
    // This works to remove all headers, just not individual headers.
    header_remove();
    if ($name !== null) {
      foreach ($headers as $header) {
        header($header);
      }
    }
  },
  true
);
?>